CLASS A EXAMPLE 2
Wednesday, October 29, 2008
last class a
20.100.55.3 / 26
multiple of 8 again .. it ends at 24...to get to 26 we need to have two bits .. so tick two bits vertically and horizontally in the table two ..
under subnets it stopped at 192
so our subnet mask is
255.255.255.192
and under bits it stopped at 64 .. so the subnets increment at rate of 64
lets start with zero subnet
subnet------------firsthost---------lasthost----------------broadcast
20.0.0.0
20.0.0.64
20.0.0.128
20.0.0.192
etc
etc till our ip
20.100.55.0----------20.100.55.1----------20.100.55.62---------20.100.55.63
our ip falls here ..
20.100.55.64
20.100.55.128
20.100.55.192
hence in this way this can be determined
the crucial one
bits---------128-------64-----32------16----8--------4-----2---------1
subnets-----*-----------*
128---------------------------------*
192---------------------------------*
224
240
248
252
254
255
powers of 2 --------------------------------------- subnets--------------------------------------hosts (-2)
2
4
8
16
32
64
128
256
512
1024